Question

The velocity of an object with a mass of `8 kg` is given by `v(t)= sin 4 t+ cos 13 t`. What is the impulse applied to the object at `t= ( 3 pi)/ 4`?

Answer 1

`bar J=5,656 " N.s"`

Explanation:

`bar J=int F(t)*d t`
`F=m*a=m*(d v)/(d t)`
`bar J=int m*(d v)/(d t)*d t`
`bar J=m int d v`
`d v=(4cos4t -13sin13t)*d t`
`bar J=m int (4cos4t-13sin13t)*d t`
`bar J=m(sin4t+cos13t)`
`bar J=8(sin4*3pi/4+cos13*3pi/4)`
`bar J=8*(0+0,707)`
`bar J=8*0,707`
`bar J=5,656 " N.s"`