The velocity of an object with a mass of #8 kg# is given by #v(t)= sin 4 t+ cos 13 t #. What is the impulse applied to the object at #t= ( 3 pi)/ 4 #?

1 Answer
Feb 9, 2016

Answer:

#bar J=5,656 " N.s"#

Explanation:

#bar J=int F(t)*d t#
#F=m*a=m*(d v)/(d t)#
#bar J=int m*(d v)/(d t)*d t#
#bar J=m int d v#
#d v=(4cos4t -13sin13t)*d t#
#bar J=m int (4cos4t-13sin13t)*d t#
#bar J=m(sin4t+cos13t)#
#bar J=8(sin4*3pi/4+cos13*3pi/4)#
#bar J=8*(0+0,707)#
#bar J=8*0,707#
#bar J=5,656 " N.s"#