The width of a rectangle is 18 yards more than the length. the perimeter is 164 yards, find the length and width?

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Answer 1 · 2018-03-29T02:10:04

#w = 91# yds; #" "l = 73# yds

Given: rectangle with #"width" = 18 + "length"; " "P = 164 yds#

Variables: #w = #width; #" "l = #length

Two equations:

#w = 18 + l; " " P = l + w = 164#

Use substitution to solve for the length:

#l + 18 + l = 164#

#2l + 18 = 164#

#2l + 18 - 18 = 164 - 18#

#2l = 146#

#l = 73# yds

Solve for the width:

#w = 18 + 73 = 91# yds