# There are 31 tickets for line leader, 10 tickets for paper passer and 19 tickets for book collector. If ray select a ticket from a box. What is the probability that he will pull out a ticket for Line Leader?

May 13, 2016

$\frac{31}{60}$

#### Explanation:

There are a total of 31+10+19=60 tickets

Now the probability (P) of an event P(event) equals

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{\text{P(event)"=("number of favourable outcomes")/"Total possible outcomes}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

Here the favourable event is 'pulling' out a Line Leader ticket of which there are 31.
The total number of possible outcomes is 60.

$\Rightarrow \text{P(line leader)} = \frac{31}{60}$