Question

There exists integer `x,y,z` satisfying `28x+30y+31z=365` then the value of `z-2x` for some such triplet is?

Answer 1

In English calendar year (not leapyear) of 365 days there exist one month of 28 days ,4 months of 30 days and 7 months of 31days .

So `28xx1+30xx4+31xx7=365`

Comparing with given relation

`28x+30y+31z=365`

We get `x=1,y=4andz=7`

Hence `z-2x=7-2*2=5`