# Triangle A has an area of 12  and two sides of lengths 7  and 7 . Triangle B is similar to triangle A and has a side with a length of 19 . What are the maximum and minimum possible areas of triangle B?

Dec 21, 2017

Area of triangle B = 88.4082

#### Explanation:

Since triangle A is isosceles, triangle B will also be isosceles.

Sides of Triangles B & A are in the ratio of 19 : 7

Areas will be in the ratio of ${19}^{2} : {7}^{2} = 361 : 49$

$\therefore A r e a o f \triangle B = \frac{12 \cdot 361}{49} = 88.4082$