# Two 0.68 Fµ capacitors are connected in series across a 10 kHz sine wave signal source. What is the total capacitive reactance?

Jun 16, 2015

${X}_{C} = 46.8 \Omega$

#### Explanation:

If I remember correctly, Capacitive Reactance should be:
${X}_{C} = \frac{1}{2 \pi f C}$
Where:
$f$ is the frequency
$C$ Capacitance
For capacitors in series:
$\frac{1}{C} = \frac{1}{C} _ 1 + \frac{1}{C} _ 2$
So $C = 3.4 \times {10}^{-} 7 F$
So:
${X}_{C} = \frac{1}{2 \pi \cdot 3.4 \times {10}^{-} 7 \cdot 10000} = 46.8 \Omega$