Two boys start running straight toward each other from two points that are 100m apart.One runs with a speed of 5m/s,while other moves at 7m/s.How close are they to the slower one's starting point when they meet?

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Answer 1 · 2017-07-24T04:56:31

Let the two boys meet after #t# sec their start.

So

#5t+7t=100#

#=>t=100/12=25/3# s

The distance of meeting point is #25/3xx5=125/3# m apart from the starting point of slower boy.