Two bulbs 100W,250V and 200W,250V are connected in series across a 500V line. Then what will happen?? a)100W will fuse b)200W will fuse c)both will fuse d)no bulb will fuse
The 100W bulb will fuse soon.
The 100W bulb has a resistance =
The 200 W bulb resistance will be half above = 312.5ohms
Total resistance in series - 937.5 ohms
So total series current =
Power dissipated in Bulb 1:
Power dissipated in Bulb 2 wil be half above: 88.5 W
Bulb1 , a 100W unit, will eventually burnout.