Two charges each of magnitude Q are fixed at 2a distance apart. A third charge (-q of mass 'm') is placed at the mid point of the two charges; now -q charge is slightly displaced perpendicular to the line joining the charges then find its time period ?
(1)#2pisqrt((ma^3piepsilon_@)/(Qq))#
(2)#2pisqrt((2ma^3piepsilon_@)/(Qq))#
(3)#pisqrt((ma^3piepsilon_@)/(Qq))#
(4)#pisqrt((2ma^3piepsilon_@)/(Qq))#
(1)
(2)
(3)
(4)
1 Answer
(2)
Explanation:
For a small displacement
The force vector acting on the particle is the negative derivative wrt
By Taylor/Binomial expansion, for small
In otherwords
So from
Therefore;