Question

Two charges of `-1 C` and `2 C` are positioned on a line at points `-2` and `2`, respectively. What is the net force on a charge of `2 C` at `1`?

Answer 1

The answer is
`F_21=2.25**10^9`

Explanation:

We all know that they will exert force equal to
`F = kq_1**q_2//r^2`
So we can put `q_1 = 2 and q_2= 1`
As sign is never considered and r = 4 from -2 to +2..and `k=9**10^9`

You will get `2.25**10^9` as answer