Given: #tan(alpha) = 4/3# and #cot(beta) = 5/12#
If #cot(beta) = 5/12#, then #tan(beta) = 12/5#
Using the identity #tan(alpha-beta) = (tan(alpha)-tan(beta))/(1+tan(alpha)tan(beta)#
#tan(alpha-beta) = (4/3-12/5)/(1+(4/3)(12/5)#
#tan(alpha-beta) = -16/63#
Using the identity #sec(alpha-beta)= +-sqrt(1+tan^2(alpha-beta))#
#sec(alpha-beta) = +-sqrt(1+(-16/63)^2)#
Because we are told that #alpha# and #beta# are in the first quadrant and we observe that #tan(alpha-beta)# is negative, we conclude that #alpha-beta# is in the fourth quadrant and, therefore, the secant is positive:
#sec(alpha-beta) = 65/63#
Using the identity #sec(theta) = 1/cos(theta)#
#cos(alpha-beta) = 63/65#
Using the identity #tan(alpha-beta) = sin(alpha-beta)/cos(alpha-beta)#
#sin(alpha-beta) = -16/63 63/65#
#sin(alpha-beta) = -16/65#