# Under a pressure of 200 kPa, a confined gas has a volume of 2,500 cubic meters. The pressure acting on the gas is increased to 500 kPa. What is the new volume of the gas if the temperature remains the same?

${V}_{2} = 1000 {m}^{3}$
Use the Boyle's Law: ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$ . substituting and making the units consistent: $\left(200 \times {10}^{3}\right) \left(2500\right) = \left(500 \times {10}^{3}\right) \left({V}_{2}\right)$. solve for ${V}_{2}$ .