Under isobaric conditions (2.0x10^5Pa) a gas expands & does 500j of work. what is the change in its volume?

1 Answer
Apr 8, 2018

#2.5times 10^-3"m"^3 = 2.5 # liters

Explanation:

The work done during an isobaric change is given by

#W = int_(V_1)^(V_2) PdV = P int_(V_1)^(V_2) dV = P(V_2-V_1) #

Thus, in our case, the change in volume is

#V_2-V_1 = W/P = (500" J")/(2.0times 10^5" Pa") = 2.5times 10^-3"m"^3#