Unknown solution of CH3COOH of 20mL is titrated against a solution of 0.031 mol L^-1 NaOH. 10mL of the base solution is required to reach the equivalence point. Calculate to concentration of the CH3COOH solution?

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Answer 1 · 2018-02-14T12:46:32

#0.0155"mol"/"L"#

We use the formula #c_1V_1=c_2V_2#, where:

#c# is the concentration of the substance, and
#V# the its volume.

Here, we have:

#c_1=0.031"mol"/"L"#

#V_1=0.01"L"#

#V_2=0.02"L"#

Rearranging to solve for #c_2#, we get:

#c_2=(c_1V_1)/V_2#

Input:

#c_2=(0.031*0.01)/0.02#

#c_2=0.0155"mol"/"L"#