Urgent. Please help. Calculate the percentage uncertainty for the displacement when t = 40s?

enter image source here

1 Answer
May 10, 2018

See below:


when #t=40#, #x approx 3 cm#

Each square in the vertical direction represents 0.4 cm (from my point of view), so the bar stretches approximately across 0.5 cm.

So the percentage uncertainty is, therefore:

#0.5/3.0 approx 0.167 times 100=17%# (two sig.figs)