Use a factor tree to find the prime factors of 72. Write the prime factorization using exponents. ?

I confused about the exponents & prime factorization.

2 Answers

#2^3 xx 3^2#

Explanation:

# 72 /2 = 2 xx 36 #

# 2 xx 36/2 = 2 xx 2 xx 18 #

# 2 xx 2 xx 18/2 = 2 xx 2 xx 2 xx 9 #

# 2 xx 2 xx 2 xx 9/3 = 2 xx 2 xx 2 xx 3 xx 3 #

# 2 xx 2 xx 2 xx 3 xx 3 = 2^3 xx 3^2 #

an exponent gives the number of times a factor is multiplied by itself. 2 is multiplied by itself 3 times so # 2^3#

Feb 24, 2018

#72 = 2xx2xx2xx3xx3 = 2^3 xx 3^2#

Explanation:

You want to write #72# as the product (multiplication) of the factors which are all prime numbers. (Numbers such as #2,3,5,7,11,...)

To use a factor tree ( also called the branch method), start with any two factors of #72# and then expand each until you get to a prime factor (they are shown in blue)

#color(white)(wwwwwwwwwwww)72#
#color(white)(wwwwxxxwwwww)"/"color(white)(x)"\"#
#color(white)(wwwwwwwwwww)8" "9#
#color(white)(wwwwx.xxx ww)"/ \"" ""/\"#
#color(white)(wwwwwwwww)4" "color(blue)(2" "3" "3)#
#color(white)(wwwwx.xww)"/ \"#
#color(white)(xxxxx.xxx)color(blue)(2" "2)#

From this we see #72 = 2xx2xx2xx3xx3 = 2^3 xx 3^2#

It does not matter which factors you start with.

#color(white)(wwwwwwwwwwww)72#
#color(white)(wwwwxxxwwwww)"/"color(white)(x)"\"#
#color(white)(wwwwwwwwwww)6" "12#
#color(white)(wwwwx.xxx ww)"/ \"" ""/\"#
#color(white)(wwwwwwwww)color(blue)(2" "3" "3)" "4#
#color(white)(wxxxxxxxx.wwwx.xww)"/ \"#
#color(white)(xxxxxxxxxxxxxx.xxx)color(blue)(2" "2)#

#72 = 2xx3xx3xx2xx2 = 2^3 xx 3^2#

Here is another possibility:

#color(white)(wwwwwwwwwwww)72#
#color(white)(wwwwxxxwwwww)"/"color(white)(x)"\"#
#color(white)(wwwwwwwwwww)color(blue)(2)" "36#
#color(white)(wwwwx.xxxwww. ww)"/ \"#
#color(white)(wwwwwwwwx.xxxw)6" "6#
#color(white)(wwwwx.xxxxx.ww)"/ \" " / \"#
#color(white)(xxxxxxxxxxxxx)color(blue)(2" "3color(white)(.)2" "3)#

#72 = 2xx2xx3xx2xx3 = 2^3 xx 3^2#