Use conventional cell notation to draw the copper-silver cell and calculate the standard E.M.F of the cell and write a balanced equation for the overall cell reaction?

1 Answer
May 7, 2018

Here's what I get.

Explanation:

The half-reactions are

#color(white)(mmmmmmmmmmmmmmmmmmmmmmmmmmmm)ul(color(white)(l)E^@"/V"color(white)(l))#
Cathode: #2×["Ag"^"+""(aq)" + "e"^"–" → "Ag(s)"]; color(white)(mmmmmmmmll)"+0.7994"#
Anode:#color(white)(mmmll)ul("Cu"^"2+""(aq)" + "2e"^"–" → "Cu(s)"]; color(white)(mmmmmmmm)ul("+0.337)#
Cell:#color(white)(mmmmm)"Cu(s)" + "2Ag"^"+""(aq)" → "Cu"^"2+""(aq)" + "2Ag(s)"; "+0.462"#

In standard cell notation, the anode is on the left:

#"Cu(s)|Cu"^"2+""(aq)||Ag"^"+""(aq)|Ag(s)"#

#E_text(cell)^@ = E_text(cathode)^@ - E_text(anode)^@ = "(0.7994 - 0.337) V" = "0.462 V"#

The overall cell reaction is

#"Cu(s)" + "2Ag"^"+""(aq)" → "Cu"^"2+""(aq)" + "2Ag(s)"#