# Use divergent test to determine convergence of the following series?

## ${\sum}_{n = 0}^{\infty} {\left(\frac{\pi}{e}\right)}^{n}$

This is like a basic geometric series: if $| r | > 1$, then it's divergent, and if $| r | < 1$, then it's convergent.
Since $\pi > e$, $r > 1$, therefore the series is divergent.