Use the limit definition to find the derivative of #5+4x-2x^2#?

#5+4x-2x^2#

1 Answer
May 14, 2018

#4-4x#

Explanation:

#lim_(h->0) 5+4x-2x^2#

#lim_(h->0)(5+4(x+h)-2(x+h)^2-(5+4x-2x^2))/h#

#lim_(h->0) (5+4x+4h-2x^2-4xh-2h^2-5-4x+2x^2)/h#

#lim_(h->0)(4h-4xh-2h^2)/h#

#lim_(h->0)((h)(4-4x-2h))/h#

#lim_(h->0)4-4x-2h#

= #4-4x#