Question

Use the sine rule to find two triangles where: ∠A = 49∘, a = 29, b = 32.?

Answer 1

See explanation below

Explanation:

The sin rule states that `a/sinA=b/sinB=c/sinC` where a,b, c are the triangle legs and A,B, C are the angles

Using that formula, we have in our case

`29/sin49=32/sinB` transposing terms

`sinB=32·sin49/29=0.8327829851`

`arcsen 0.8327829851=56º23´8.5´´`

Then `C=180-(49+56º23´8,5´´)=74º 36´51.5´´`

And finally `29/sin49=c/(sin74º36´51.5´´)`

`c=37.04827`