Using dimensional analysis calculate the number of seconds in 0.55 years?

1 Answer
Feb 22, 2018

#17,107,200 \ "seconds"#

Explanation:

Dimensional analysis, here we go!

#0.55 \ "years"=0.55color(red)cancelcolor(black)"years"*(12 \color(red)cancelcolor(black) "months")/(1color(red)cancelcolor(black)"year")*(30color(red)cancelcolor(black) "days")/(1color(red)cancelcolor(black)"month")*(24color(red)cancelcolor(black)"hours")/(1color(red)cancelcolor(black)"day")*(60color(red)cancelcolor(black)"minutes")/(1color(red)cancelcolor(black)"hour")*(60 \ "seconds")/(1color(red)cancelcolor(black)"minute")=17,107,200 \ "seconds"#

Note that for the months, I have used #30# days.