# Using dimensional analysis calculate the number of seconds in 0.55 years?

Feb 22, 2018

$17 , 107 , 200 \setminus \text{seconds}$
$0.55 \setminus \text{years"=0.55color(red)cancelcolor(black)"years"*(12 \color(red)cancelcolor(black) "months")/(1color(red)cancelcolor(black)"year")*(30color(red)cancelcolor(black) "days")/(1color(red)cancelcolor(black)"month")*(24color(red)cancelcolor(black)"hours")/(1color(red)cancelcolor(black)"day")*(60color(red)cancelcolor(black)"minutes")/(1color(red)cancelcolor(black)"hour")*(60 \ "seconds")/(1color(red)cancelcolor(black)"minute")=17,107,200 \ "seconds}$
Note that for the months, I have used $30$ days.