Using locus fund the equation of the circle whose centre is at (-3,-2) and radius 8 units?

1 Answer
Jim G.
Mar 9, 2018

#(x+3)^2+(y+2)^2=64#

Explanation:

#"the equation of a circle in standard form is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#

#"where "(a,b)" are the coordinates of the centre and r"#
#"is the radius"#

#"here "(a,b)=(-3,-2)" and "r=8#

#(x-(-3))^2+(y-(-2))^2=8^2#

#rArr(x+3)^2+(y+2)^2=64larrcolor(blue)"equation of circle"#

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