# Using the following information to help you answer parts (a) - (c): HNO3 + NaOH ---> NaNO3 + H2O ?

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RAM: H = 1 NA = 23 0 = 16 N = 14

A) if you have 0.55 moles of HNO3 how many oxygen atoms would you have?

B) If 0.365g of NaOH is reacted with an excess of HNO3 what is the maximum mass of NaNO3 which could be recovered?

C) 12.05cm3 of a 0.2065 M aqueous NaOH solution is titrated to the end-point by 25.05 cm3 of HNO3 solution. What is the concentration of the HNO3?

RAM: H = 1 NA = 23 0 = 16 N = 14

A) if you have 0.55 moles of HNO3 how many oxygen atoms would you have?

B) If 0.365g of NaOH is reacted with an excess of HNO3 what is the maximum mass of NaNO3 which could be recovered?

C) 12.05cm3 of a 0.2065 M aqueous NaOH solution is titrated to the end-point by 25.05 cm3 of HNO3 solution. What is the concentration of the HNO3?

##### 1 Answer

We, can conclude that,

**A) If I have #0.55 " moles of " HNO_3# how many oxygen atoms would I have?**

Each molecule of

**B) If I react #0.365"g of "NaOH# with an excess of #HNO_3# what is the maximum mass of #NaNO_3# that would be recovered?**

number of mole of

As

**C) #12.05cm^3# of a #0.2065 M# aqueous #NaOH# solution is titrated to the end-point by #25.05 cm^3# of #HNO_3# solution. What is the concentration of the #HNO_3#?**

Let,

By the formula,