Question

Vector A points to the north and has length A. Vector B points to the east and has length B=2.0A. How do you find the magnitude of C=3.6A+B in terms of A?

Answer 1

The answer is `=4.12A`

Explanation:

The vectors are the following :

`vecA= <0,1> A`

`vecB= <2,0>A`

`vecC=3.6vecA+vecB`

`=(3.6 xx<0,1> )A+<2,0>A`

`= <2, 3.6> A`

The magnitude of `vecC` is

`=||vecC|| = ||<2, 3.6>||A`

`=sqrt(2^2+3.6^2)A`

`=4.12A`