Question

We have `f:RR->RR;f(x)=x(x-2)`.Is `f` differentiable on `x=2`?

Answer 1

Yes.

Explanation:

`f(x) = x^2-2x`, so `f'(x) = 2x-2` which exists for all `x`.

So `f'(2)` exists and `f` is differentiable at `2`.