# What are the absolute extreme values of the function #f(x) = x/sqrt(x^2+1)# on the interval #[0,2]#?

##### 1 Answer

Aug 3, 2017

This function is strictly increasing on the given interval, so the absolute minimum value is

#### Explanation:

By the Quotient Rule and Chain Rule, the derivative of this function is

This can be simplified by multiplying the top and bottom by

From this, we see that