# What are the asymptote(s) and hole(s), if any, of  f(x) =e^-x/(1-x) ?

##### 1 Answer
Mar 19, 2016

A hole is the values of x for which the denominator becomes zero. It is $x = 1$.

#### Explanation:

Exponential -x decreases toward zero asymptotically (it never reaches it). The hole is $x = 1$