# What are the boundaries of x and y if (x-2)^2+(y-3)^2 >=16, (x-3)^2+((y-4)^2/64)<1?

${\left(x - 2\right)}^{2} + {\left(y - 3\right)}^{2} \ge 16$ defines the exterior of a circumference centered at $\left\{2 , 3\right\}$ with radius $4$
${\left(x - 3\right)}^{2} + {\left(y - 4\right)}^{2} / 64 \le 1$ defines the interior of an ellipse centered at $\left\{3 , 4\right\}$ having axes $1 , 8$