What are the center and radius of a circle whose equation is #(x-A)^2 + (y-B)^2 = C#?

1 Answer
Jan 1, 2016

The circle has a center at #(A,B)# and a radius of #sqrtC#.

Explanation:

The typical standard form of a circle:

#(x-h)^2+(y-k)^2=r^2#

where #(h,k)# is the center and #r# is the radius.

Thus, #(A,B)# is the center. To find the radius, set

#C=r^2#
#r=sqrtC#

The circle has a center at #(A,B)# and a radius of #sqrtC#.