What are the components of the vector between the origin and the polar coordinate #(6, (3pi)/4)#?

1 Answer
Feb 12, 2016

# ((-3sqrt2),(3sqrt2))#

Explanation:

using the formulae that links Polar to Cartesian coordinates.

#• x = rcostheta #

#• y = rsintheta #

in this question: r = 6 and # theta = (3pi)/4 #

# rArr x = 6cos((3pi)/4) = 6.(- 1/sqrt2) = -3sqrt2 #

[note : # 1/sqrt2 = sqrt2/(sqrt2 .sqrt2) = 1/2 sqrt2] #

and using exact values for # cos((3pi)/4)color(black)(" and ") sin((3pi)/4)#

# rArr y = 6sin((3pi)/4) = 6.(1/sqrt2) = 3sqrt2 #