Question

What are the components of the vector between the origin and the polar coordinate `(-9, (5pi)/6)`?

Answer 1

`x=9*sqrt3/2`
`y=-9/2`

Explanation:

`r=-9" "theta=(5pi)/6`
`x=r*cos theta" "y=r*sin theta`
`theta=(5pi)/6*180/pi=150^o`
`x=-9*cos 150`
`x=9*sqrt3/2`
`y=-9*sin150`
`y=-9*1/2`
`y=-9/2`