# What are the correct values of #x# in the equation #4x^2 = y# when #y = 144#?

##### 1 Answer

Dec 28, 2015

x' = +6; x" = -6

#### Explanation:

First, we pass the "4" that multiplies x to divide 144:

Then, we have to pass the square of x to the other side, with its value inverted: