What are the critical values, if any, of #f(x)= (x-2)(x+5)(x-7)*lnx#?

1 Answer
Feb 17, 2016

They are approximately #1.452# and #5.136#.

Explanation:

#f(x) = (x^3-4x^2-31x+70)lnx#

Use the product rule to find

#f'(x)=(3x^2-8x-31)lnx + (x^2-4x-31+70/x)#

#f'(x)# is defined for all #x# in the domain of #f#.

So the critical value will be the solutions to

#(3x^2-8x-31)lnx + (x^2-4x-31+70/x) = 0#

Use whatever technology or approximation technique you have available to find that the solutions are approximately #1.452# and #5.136#.