# What are the extrema of #f(x)=(x^2)/(x^2-3x)+8 # on #x in[4,9]#?

##### 1 Answer

Jun 10, 2018

The given function is always decreasing and therefore has neither maximum nor minimum

#### Explanation:

The derivative of the function is

and

The given function the function is always decreasing and therefore has neither maximum nor minimum

graph{x^2/(x^2-3x)+8 [-0.78, 17, 4.795, 13.685]}