What are the first four terms in the binomial expansion of #(1+2x)^5#?

1 Answer
Shwetank Mauria
Aug 11, 2017

First five terms of #(1+2x)^5# are #1#, #10x#, #40x^2# and #160x^3#.

Explanation:

Expansion of binomial terms of #(1+a)^5# using Pascal's triangle is

#1+5a+10a^2+10a^3+5a^4+a^5#

Hence first five terms of #(1+2x)^5# are

#1#, #5(2x)=10x#, #10(2x)^2=40x^2# and #10(2x)^3=160x^3#.

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