# What are the important parts of the equation to graph f(x) = (x-2)^2 - 1?

Oct 13, 2015

Vertex is $\left(2 , - 1\right)$
Axis of Symmetry is $x = 2$
The curve is opening upwards.

#### Explanation:

$y = {\left(x - 2\right)}^{2} - 1$

It is in the vertex form.

$y = a {\left(x - h\right)}^{2} + k$

Th vertex of the given function is -

$h = - 1 \left(- 2\right) = 2$
$k = - 1$
Vertex is $\left(2 , - 1\right)$

Axis of Symmetry is $x = 2$

Its $a$ value is $1$ i.e., positive.
Hence the curve is opening upwards.

graph{(x-2)^2-1 [-10, 10, -5, 5]}