What are the important parts of the equation to graph #f(x) = (x-2)^2 - 1#?

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Answer 1 · 2015-10-13T00:01:37

Vertex is #(2,-1)#
Axis of Symmetry is #x=2#
The curve is opening upwards.

#y=(x-2)^2-1#

It is a quadratic equation.
It is in the vertex form.

#y=a(x-h)^2+k#

Th vertex of the given function is -

#h=-1(-2)=2#
#k=-1#
Vertex is #(2,-1)#

Axis of Symmetry is #x=2#

Its #a# value is #1# i.e., positive.
Hence the curve is opening upwards.

graph{(x-2)^2-1 [-10, 10, -5, 5]}