What are the important points needed to graph # F(x) = (x-7)^2-3#?

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Answer 1 · 2015-10-27T10:37:35

Refer Explanation

#y=(x-7)^2-3#

Its vertex is -

x co-ordinate of the vertex is #-(-7)=7#
y co-ordinate of the vertex is #-3)#

At #(7, - 3)# the curve turns.

Since #a# is positive, the curve opens upward. It has a minimum at #(7, - 3)#

Take two points on either side of #x=7#.
Find the corresponding #y# values.

x: y
5: 1
6: -2
7: -3
8: -2
9: 1

graph{(x-7)^2-3 [-10, 10, -5, 5]}