# What are the important points needed to graph #y = 3x^2 + 8x - 6#?

##### 1 Answer

Oct 28, 2015

Its vertex is

Since the co-efficient of

It has a minimum at

Its y- intercept is

#### Explanation:

Given-

#y=3x^2+8x-6#

We have to find the vertex

#x=(-b)/(2a)=(-8)/(2 xx 3)=(-8)/6=(-4)/3#

At

#y=3((-4)/3)^2+8((-4)/3)-6#

#y=3((16)/9)-32/3-6#

#y=48/3-32/3-6=(-2)/3#

Its vertex is

Take two points on either side of

Find the y values. Plot the points. Join them with a smooth curve.

Since the co-efficient of

It has a minimum at

Its y- intercept is

Since the co-efficient of

graph{3x^2+8x-6 [-25.65, 25.65, -12.83, 12.82]}