What are the intercepts for #y=2x^2-10x-1#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer ali ergin Apr 21, 2016 #y=-1# #x_1=0,098# #x_2=5,098# Explanation: #y=2x^2-10x-1# #"for x="0" "rArry=-1 # #"for y="0# #2x^2-10x-1=0# #Delta=sqrt(100+4*2*1)" "Delta=sqrt(108)" "Delta=10,39# #x_1=(10-10,39)/4# #x_1=(0,39)/4# #x_1=0,098# #x_2=(10+10,39)/4# #x_2=(20,39)/4# #x_2=5,098# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1278 views around the world You can reuse this answer Creative Commons License