# What are the intercepts for y=x^2-5x+4?

Jun 16, 2017

$y = 4 \text{ and } x = 1 , x = 4$

#### Explanation:

$\text{to obtain the intercepts}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercepts"

$x = 0 \to y = 4 \leftarrow \textcolor{red}{\text{ y-intercept}}$

$y = 0 \to {x}^{2} - 5 x + 4 = 0$

$\Rightarrow \left(x - 1\right) \left(x - 4\right) = 0$

$\Rightarrow x = 1 , x = 4 \leftarrow \textcolor{red}{\text{ x-intercepts}}$ graph{x^2-5x+4 [-10, 10, -5, 5]}