Question

What are the intercepts of `19x+6y=-17`?

Answer 1

The y-intercept of the equation `19x + 6y = -17` is `-17/6` and the x-intercept is `-17/19`.

Explanation:

To get the y-intercept of a linear equation, substitute `0` for `x`.
`19*0+6y = -17`
`6y = -17`
`y = -17/6`
The y-intercept is `-17/6`.

To get the x-intercept of a linear equation, substitue `0` for `y`.
`19x+6*0 = -17`
`19x = -17`
`x = -17/19`
The x-intercept is `-17/19`.