What are the intercepts of #2y-x=1#? Algebra Graphs of Linear Equations and Functions Intercepts and the Cover-Up Method 1 Answer Tony B Nov 19, 2015 #"x-intercept" -> (-1,0)_("y=0")# #"y-intercept" -> (0,1/2)_("x=0")# Explanation: Given: #2y-x=1# #2y =x+1# #y=1/2x+1/2# At #x=0 , y= 1/2# At #y=0, x=-1# So #"x-intercept" -> (-1,0)_("y=0")# #"y-intercept" -> (0,1/2)_("x=0")# Answer link Related questions How do you use the cover-up method to solve for the x and y intercept? What are the intercepts for horizontal and vertical line graphs? What are the intercepts for #3x-4y=-5#? How do I determine the x and y intercept for the graph #6(x-1)=2(y+3)#? How do you graph #5x+y=5# using the intercepts? What needs to be done to the equation #3(x+2)=2(y+3)# before you can use either method to find... What are the intercepts for the #y=0# and #x=0# graphs? How do you sketch a graph with x-intercept of 1 and y-intercept of -5? How do you graph #2x - 3y = 9# using x- and y- intercepts? How do you use the intercepts to graph the equation #2x-4y=8#? See all questions in Intercepts and the Cover-Up Method Impact of this question 6868 views around the world You can reuse this answer Creative Commons License