What are the intercepts of : #5y= 7x - 19#?

3 Answers
Mar 9, 2018

Answer:

#x = 19/7#

#y = -19/5#

Explanation:

To find the #x#-intercept, we set #y# equal to #0# and solve:

#5 xx 0 = 7 xx x - 19#

#19 = 7x#

#x = 19/7#

Now we solve for when #x = 0# to get the #y#-intercept:

#5 y = 7 xx 0 - 19#

#5 y = -19#

#y = -19/5#

To check our work, let''s graph the equation and make sure our intercepts are correct

graph{5y = 7x-19}

Yep, we were right!

Mar 9, 2018

Answer:

#x# intercept #= 19/7, y # intercept #= -19/5#

Explanation:

To find the x-intercept of a given linear equation, plug in 0 for 'y' and solve for 'x'.

To find the y-intercept, plug 0 in for 'x' and solve for 'y'.

Given equation is #5y = 7x - 19#

To find x intercept : when y = 0,

#7x - 19 = (5*0) = 0#

#7x = 19# or #x = 19/7#

To find y intercept : when x = 0,

#(7*0) - 19 = 5y#

#5y = -19# or #y = -19/5#

#color(purple)(y = (7x-19) / 5#
graph{(7x - 19) / 5 [-10, 10, -5, 5]}

Mar 9, 2018

Answer:

The x-intercept is #(19/7,0)# or #~~(2.714,0)#.

The y-intercept is #(0,-19/5)# or #(0,-3.8)#.

Explanation:

Given:

#5y=7x-19#

Solve for #y# to get the equation into slope-intercept form:

#y=mx+b,#

where:

#m# is the slope, and #b# is the y-intercept.

#5y=7x-19#

Divide both sides by #5#.

#y=(7x)/5-19/5#

The y-intercept is the value of #y# when #x=0#.

The y-intercept is #(0,-19/5)# or #(0,-3.8)#

The x-intercept is the value of #x# when #y=0#.

Substitute #0# for #y# and solve for #x#.

#0=(7x)/5-19/5#

Multiply both sides by #5#.

#5xx0=7x-19#

Simplify.

#0=7x-19#

Add #19# to both sides.

#19=7x#

Divide both sides by #7#.

#19/7=x#

The x-intercept is #(19/7,0)~~(2.714,0)#

graph{y=7/5x-19/5 [-10, 10, -5, 5]}