# What are the intercepts of : 8y= - 2x - 9?

Apr 9, 2016

$x$ intercept: $\left(- \frac{9}{2} , 0\right)$
$y$ intercept: $\left(0 , - \frac{9}{8}\right)$

#### Explanation:

$x$ intercepts where $y = 0$
Therefore, substitute $y = 0$ and solve for $x$.

$0 = - 2 x - 9$
$9 = - 2 x$
$- \frac{9}{2} = x$

Therefore, $x$ intercept at $\left(- \frac{9}{2} , 0\right)$

$y$ intercepts where $x = 0$
Therefore, substitute $x = 0$ and solve for $y$.

$8 y = - 9$
$y = - \frac{9}{8}$

Therefore, $y$ intercept at $\left(0 , - \frac{9}{8}\right)$