What are the intercepts of the line #y = –2x + 8#?

3 Answers
Apr 9, 2018

Answer:

the answer is #y=8# and #x=4#

Explanation:

see this graph:https://www.desmos.com/calculator/r4vhmjhwyy
you already know that the y-int would be #8# from the graph b/c remember the formula #y=mx+b# and the #b# would always be your y-int and then you just have to graph to find what the #x# is

Apr 9, 2018

Answer:

The #y#-intercept is #(0,8)#.
The #x#-intercept is #(4,0)#.

Explanation:

To find the #y#-intercept, plug in #0# for #x# and you solve to get #8#

#y=-2x+8#

#y=-2(0)+8#

#y=0+8#

#y=0#

To find the #x#-intercept, plug in #0# for #y# and you solve to get #4#

#y=-2x+8#

#0=-2x+8#

#2x=8#

#x=0#

Apr 9, 2018

Answer:

The y-intercept is #(0,8)#
The x-intercept is #(4,0)#

Explanation:

y-intercept: you make #x=0# so y= 0+8 so y intercept is(0,8)
x-intercept: you make #y=0# so #0=-2x+8##=># #-2x=-8# so x-intercept is #(4,0)#