What are the intercepts of #y=2x+6#?

2 Answers
May 1, 2018

Answer:

y-intercept : #6#
x-intercept : #-3#

Explanation:

Interception of #x# can be found by assuming the value of #y# to be #0# since this is how #x# can intercept #y#, by reaching it's axis with a value of #0#.

Same goes with interception of #y#.

Regarding your question :

#y = 2x + 6#

By using the formulae #y=mx+c#
#c# stands for #y#-intercept
#y#-intercept = 6

To find #x#-intercept, #y=0#
#0 = 2x+6#
#x#-intercept = #-3#

May 1, 2018

Answer:

#y#-Int. #= 6#

#x#-Int. =#-3#

Explanation:

To find the #x# intercept, you let #y=0#

#2x+6 = 0#

Then you minus #6# on both sides

#2x=-6#

Then you divide by #2# on both sides

#x=-3#

To find the #y#-intercept, you let #x=0#

#y = 2xx0+6#

#y = 0+6#

#y=6#