# What are the mean and standard deviation of a binomial probability distribution with n=8  and p=7/29 ?

mean$= \frac{56}{29}$
standard deviation$= \frac{4 \sqrt{77}}{29}$
mean$= n p = 8 \cdot \frac{7}{29} = \frac{56}{29}$
standard deviation$= \sqrt{n p \left(1 - p\right)} = \sqrt{8 \cdot \frac{7}{29} \cdot \frac{22}{29}} = \frac{4 \sqrt{77}}{29}$