What are the mean and standard deviation of a binomial probability distribution with n=12  and p=5/37 ?

Nov 18, 2015

"Mean" = 12*5/37 = 60/37 = 1.62

"Standard deviation" = (12*5/37*32/37)^(1/2) = 1.18

Explanation:

$\text{Mean" = "n"*"p}$

"SD" = ("n"* "p"*"q") ^(1/2)

$\text{q" = 1-"p}$