What are the scalar equations of the equation of the line through the point (4,-6,-3) and perpendicular to the plane 5 x+y+2 z=7? Also I have to write the answer in the form [a+bs, c+ds, e+f*s] where s is a parameter.

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Answer 1 · 2017-10-05T12:38:36

The equation of the line is #((x=4+5s),(y=-6+1s),(z=-3+2s))#, #AA s in RR#

The equation of the plane is

#5x+y+2z-7=0#

The normal vector to the plane is

#vecn=((5),(1),(2))#

The point is #P=(4,-6,-3)#

The equation of the line is

#((x),(y),(z))=((4),(-6),(-3))+s((5),(1),(2))#

What are the scalar equations of the equation of the line through the point (4,-6,-3) and perpendicular to the plane 5 x+y+2 z=7? Also I have to write the answer in the form [a+b*s, c+d*s, e+f*s] where s is a parameter.