Question

What are the sine, cosine, and tangent of `(2pi)/3` radians?

Answer 1

`{sqrt3/2,-1/2,-sqrt3}`

Explanation:

`sin ((2pi)/3)=sin(pi-(2pi)/3)=sin(pi/3)=sqrt3/2`

`cos((2pi)/3)=-cos(pi-(2pi)/3)=-cos(pi/3)=-1/2`

`tan((2pi)/3)=-tan(pi-(2pi)/3)=-tan(pi/3)=-sqrt3`